document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=648591>Question 648591</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In a bag of M&M’s there are 12 green, 7 blue, 11 brown, 9 orange,  and 15 red candies.  If one candy is chosen from this class at random, what is the probability that the selected candy will be green or orange? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #406749 by </B><A HREF=/tutors/aboutme.mpl?userid=swincher4391><B>swincher4391(1107)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=swincher4391><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=swincher4391><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=406749\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> We have 12+7+11+9+15 M&Ms. This is 54 M&Ms. This is our sample space: S. Let E be the event that you pick a green or orange M&M. There are 12+9 Green or Orange M&Ms. That means 21 satisfy this event.  Then  P[green or orange m&m] = N(E)/N(S) =  21/54 where N(E) is just the number of elements in that set: 21. \r<BR>\n" );
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document.write( "I know that was formal so let me break it down.\r<BR>\n" );
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document.write( "You have 54 M&Ms to choose from. 21 are green or orange. When you reach in the bag, you have a 21/54 chance of picking a green or an orange. </SPAN>\n" );
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