document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=648568>Question 648568</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a= 84 inches b=44 inches c= 94.83 inches , what is the area and perimeter ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #406734 by </B><A HREF=/tutors/aboutme.mpl?userid=swincher4391><B>swincher4391(1107)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=swincher4391><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=swincher4391><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=406734\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> perimeter = (a+b+c) = (84+44+94.83) = 222.83\r<BR>\n" );
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document.write( "This means the semiperimeter or half of the perimeter is 111.415\r<BR>\n" );
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document.write( "Using Heron's formula where a,b,c are sides of the triangle:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=T+=+sqrt%28s%28s-a%29%28s-b%29%28s-c%29%29+=+sqrt%28111.415+%2A+%28111.415+-+88%29+%2A+%28111.415+-+44%29+%2A+%28111.415-94.83%29%29 ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "1707.87 in^2  is the area.\r<BR>\n" );
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