document.write( "Question 59330This question is from textbook algebra 1
\n" ); document.write( ": how would i do cubic roots in algebra.
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Algebra.Com's Answer #40666 by checkley71(8403) $\"\"$ $\"About$

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A SHORT CUT (ASSUMING THEY ARE PURE CUBE ROOTS) BREAK DOWN THE NUMBER INTO ALL IT'S FACTORS AND REMOVE ALL PAIRS OF 3 THUS
\n" ); document.write( "CUBE ROOT 27,000 DIVIDE BY 2 WE GET 13,500 DIVIDE BY 2 WE GET 6,750 NOW DIVIDE BY 2 AGAIN 3,375. SO 2(2*2*2) IS A FACTOR.
\n" ); document.write( "DIVIDE 6,750 BY 5 WE GET 375, DIVIDE BY 5 WE GET 135 DIVIDE BY 5 WE GET 27.SO 5(5*5*5) IS ANOTHER FACTOR.
\n" ); document.write( "DIVIDE 27 BY 3 WE GET 9 DIVIDE BY 3 WE GET 3 SO 3 (3*3*3) IS ANOTHER FACTOR.
\n" ); document.write( "NOW WE HAVE 2*5*3=30 WHICH IS THE CUBE ROOT OF 27,000
\n" ); document.write( "PROOF
\n" ); document.write( "30*30*30 =27,000
\n" ); document.write( "27,000=27,000
\n" ); document.write( "THE LONG FORM IS TOO COMPLEX TO TYPE HERE.
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