document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=648331>Question 648331</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What is the area of a rectangle with width 10x, the length is 3x - 74 is 2500. Please show me how you came to this answer. Thanks, elaine. I am confused<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #406642 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley79><B>checkley79(3341)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley79><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=406642\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A=L*W<BR>\n" );
document.write( "2500=10X*(3X-74)<BR>\n" );
document.write( "2500=30X^2-740X<BR>\n" );
document.write( "30X^2-740X-2500=0<BR>\n" );
document.write( "10(3X^2-74X-250)=0<BR>\n" );
document.write( "x = (-b +- sqrt( b^2-4*a*c ))/(2*a)<BR>\n" );
document.write( "X=(+74+_SQRT(-74^2-4*3*-250))/2*3<BR>\n" );
document.write( "X=(+74+-SQRT(5476-4*3*-250))/6<BR>\n" );
document.write( "X=(74+-SQRT(5476+3000))/6<BR>\n" );
document.write( "X=(74+-SQRT(8476)/6<BR>\n" );
document.write( "X=(74+_92.065)/6<BR>\n" );
document.write( "X=74+92.065)/6<BR>\n" );
document.write( "X=166.065/6<BR>\n" );
document.write( "X=27.677 ANS.<BR>\n" );
document.write( "X=(74-SQRT(8476)/6<BR>\n" );
document.write( "X=(74-92.065)/6<BR>\n" );
document.write( "X=(-17.065)/6<BR>\n" );
document.write( "X=-2.844 ANS. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );