document.write( "Question 648250: x+3y+z=6
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Algebra.Com's Answer #406634 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
 
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document.write( "Hi,
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document.write( "x+3y+z=6
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document.write( "3x+y-z=-2
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document.write( "2x+2y-z=1
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document.write( "Basic Plan:
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document.write( "·Use a pair of equations and eliminate one variable.
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document.write( "· Use a different pair of equations and eliminate the same variable.
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document.write( "·Solve the system found, determining the values of those variables.
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document.write( "·Substitute those into an original equation to find the remaining variable’s value.
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document.write( "x+3y+z=6
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document.write( "3x+y-z= -2   || Adding to eliminate z
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document.write( "  \"4x+%2B+4y+=+4\"
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document.write( "3x+y-z=-2
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document.write( "2x+2y-z=1   ||  Subtracting 2nd EQ from 1st to eliminate z
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document.write( " \"x+-+y+=+-3\"
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document.write( " 4x + 4y = 4
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document.write( "  x - y = -3     ||Multiplying 2nd EQ by 4 and adding to 1st EQ to eliminate y
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document.write( "  8x = -8
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document.write( "   x = -1  and y = 2     \"-1+-+y+=+-3\"
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document.write( " z = 1     \"-1+%2B+6++%2B+z+=+6\"
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document.write( "and..
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document.write( "\"-2%2B+4+-+1+=+1\"
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