document.write( "Question 59323: what is 2x-3y=12
\n" ); document.write( " x=4y+1\r
\n" ); document.write( "\n" ); document.write( "substituion form
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Algebra.Com's Answer #40663 by checkley71(8403)\"\" \"About 
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2X-3Y=12
\n" ); document.write( "X=4Y+1 MULTIPLY THIS EQUATION BY -2 AND ADD
\n" ); document.write( "-2X+8Y=-2
\n" ); document.write( "2X-3Y=12
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\n" ); document.write( "5Y=10
\n" ); document.write( "Y=10/5
\n" ); document.write( "Y=2
\n" ); document.write( "X=4Y+1
\n" ); document.write( "X=4*2+1
\n" ); document.write( "X=8+1
\n" ); document.write( "X=9
\n" ); document.write( "PROOF
\n" ); document.write( "2*9-3*2=12
\n" ); document.write( "18-6=12
\n" ); document.write( "12=12
\n" ); document.write( "65/5=12
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