document.write( "Question 648211: Find a number such that twice the number increased by seven is the same as four times the number decreased by three. \n" ); document.write( "
Algebra.Com's Answer #406597 by shweta(56)\"\" \"About 
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Let the required number be 'x'
\n" ); document.write( "Required equation:
\n" ); document.write( "2(x+7)=4(x-3)
\n" ); document.write( "2x+ 14=4x-12
\n" ); document.write( "2x-4x= -12-14
\n" ); document.write( "-2x=-26 ( minus sign get cancelled with each other)
\n" ); document.write( " 2x=26
\n" ); document.write( " x=26/2
\n" ); document.write( " x=13
\n" ); document.write( "Required number is 13\r
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