document.write( "Question 648119: How many quarts of pure antifreeze must be added to 7 quarts of a 50% antifreeze solution to obtain a 60% antifreeze solution?\r
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Algebra.Com's Answer #406560 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! How many quarts of pure antifreeze must be added to 7 quarts of a 50% antifreeze solution to obtain a 60% antifreeze solution? \n" ); document.write( "------ \n" ); document.write( "Equation: \n" ); document.write( "alcohol + alcohol = alcohol \n" ); document.write( "0.50*7 + x = 0.60*(7+x) \n" ); document.write( "--- \n" ); document.write( "Multiply thru by 100 to get: \n" ); document.write( "50*7 + 100x = 60*7 + 60x \n" ); document.write( "---- \n" ); document.write( "40x = 10*7 \n" ); document.write( "x = (1/4)7 \n" ); document.write( "x = 1.75 quarts (amt. of pure antifreeze needed) \n" ); document.write( "================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "=================== \n" ); document.write( " |