document.write( "Question 648119: How many quarts of pure antifreeze must be added to 7 quarts of a 50% antifreeze solution to obtain a 60% antifreeze solution?\r
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Algebra.Com's Answer #406560 by stanbon(75887)\"\" \"About 
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How many quarts of pure antifreeze must be added to 7 quarts of a 50% antifreeze solution to obtain a 60% antifreeze solution?
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\n" ); document.write( "Equation:
\n" ); document.write( "alcohol + alcohol = alcohol
\n" ); document.write( "0.50*7 + x = 0.60*(7+x)
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\n" ); document.write( "Multiply thru by 100 to get:
\n" ); document.write( "50*7 + 100x = 60*7 + 60x
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\n" ); document.write( "40x = 10*7
\n" ); document.write( "x = (1/4)7
\n" ); document.write( "x = 1.75 quarts (amt. of pure antifreeze needed)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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