document.write( "Question 648018: Solve each system by substitution\r
\n" ); document.write( "\n" ); document.write( "x - 3y = 3 and 3x + 5y = -19
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Algebra.Com's Answer #406539 by Algebraic(50)\"\" \"About 
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Original equations: \"x+-+3y+=+3\" and \"3x+%2B+5y+=+-19\"\r
\n" ); document.write( "\n" ); document.write( "Step 1: To solve by substitution, we'd have to get a variable by itself so that we can plug it into the other.\r
\n" ); document.write( "\n" ); document.write( "Let's try to get 'x' by itself on the left equation to make it easier, since it doesn't have a number already attached to it.\r
\n" ); document.write( "\n" ); document.write( "\"x+-+3y+=+3\"\r
\n" ); document.write( "\n" ); document.write( "Step 2: Add '3y' to both sides to get 'x' by itself\r
\n" ); document.write( "\n" ); document.write( "\"x+-+3y+=+3\"
\n" ); document.write( "\"x+=+3y+%2B+3\"\r
\n" ); document.write( "\n" ); document.write( "Step 3: We now have 'x' by itself and can plug it into the other equation to give us what 'y' is.\r
\n" ); document.write( "\n" ); document.write( "\"x+=+3y+%2B+3\"\r
\n" ); document.write( "\n" ); document.write( "Plug in the above into the other equation.\r
\n" ); document.write( "\n" ); document.write( "\"3x+%2B+5y+=+-19\"
\n" ); document.write( "\"3%283y%2B3%29+%2B+5y+=+-19\"\r
\n" ); document.write( "\n" ); document.write( "Step 4: Distribute the '3' to everything in the parenthesis\r
\n" ); document.write( "\n" ); document.write( "\"3%283y%2B3%29+%2B+5y+=+-19\"
\n" ); document.write( "\"9y%2B+9+%2B+5y+=+-19\"\r
\n" ); document.write( "\n" ); document.write( "Step 5: Combine like terms\r
\n" ); document.write( "\n" ); document.write( "\"9y%2B+9+%2B+5y+=+-19\"
\n" ); document.write( "\"14y%2B+9+=+-19\"\r
\n" ); document.write( "\n" ); document.write( "Step 6: Continue combining like terms.. subtract 9 to both sides to get '14'y by itself\r
\n" ); document.write( "\n" ); document.write( "\"14y%2B+9+=+-19\"
\n" ); document.write( "\"14y+=+-28\"\r
\n" ); document.write( "\n" ); document.write( "Step 7: Divide '14' to both sides to get 'y' by itself\r
\n" ); document.write( "\n" ); document.write( "\"14y+=+-28\"
\n" ); document.write( "\"y+=+-2\"\r
\n" ); document.write( "\n" ); document.write( "We now know that the 'y' point to this system of equations is \"-2\"\r
\n" ); document.write( "\n" ); document.write( "With the 'y' point, you can find the 'x' by plugging in the 'y' to any of the two given equations.\r
\n" ); document.write( "\n" ); document.write( "I'm going to use this equation to make it easier \"x+-+3y+=+3\"\r
\n" ); document.write( "\n" ); document.write( "Step 1: We know what 'y' is, so plug \"y+=+-2\" into the equation to get the 'x' point\r
\n" ); document.write( "\n" ); document.write( "\"x+-+3y+=+3\"
\n" ); document.write( "\"x+-+3%28-2%29+=+3\"\r
\n" ); document.write( "\n" ); document.write( "Step 2: Simplify\r
\n" ); document.write( "\n" ); document.write( "\"x+-+3%28-2%29+=+3\"
\n" ); document.write( "\"x+%2B+6+=+3\"\r
\n" ); document.write( "\n" ); document.write( "Step 3: Subtract '6' to both sides to get 'x' by itself\r
\n" ); document.write( "\n" ); document.write( "\"x+%2B+6+=+3\"
\n" ); document.write( "\"x+=+-3\"\r
\n" ); document.write( "\n" ); document.write( "We now know that the 'x' point to this system of equations is \"-3\"\r
\n" ); document.write( "\n" ); document.write( "The solution is \"x+=+-3\" and \"y+=+-2\"
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