document.write( "Question 648054: hi tutor,,please help me again for this question...2.how much pure alcohol must be added to a 12L of a 20% alcohol sulotion to make a solution that is 60% alcohol?
\n" ); document.write( "thank you.. \n" ); document.write( "

Algebra.Com's Answer #406536 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let $\"+x+\"$ = liters of pure alcohol to be added
\n" ); document.write( " $\"+.2%2A12+=+2.4+\"$ liters of pure alcohol in 20% solution
\n" ); document.write( "--------------
\n" ); document.write( " $\"+%28+x+%2B+2.4+%29+%2F+%28+x+%2B+12+%29+=+.6+\"$
\n" ); document.write( " $\"+x+%2B+2.4+=+.6%2A%28+x+%2B+12+%29+\"$
\n" ); document.write( " $\"+x+%2B+2.4+=+.6x+%2B+7.2+\"$
\n" ); document.write( " $\"+.4x+=+7.2+-+2.4+\"$
\n" ); document.write( " $\"+.4x+=+4.8+\"$
\n" ); document.write( " $\"+x+=+12+\"$
\n" ); document.write( "12 liters of pure alcohol need to be added
\n" ); document.write( "check:
\n" ); document.write( " $\"+%28+x+%2B+2.4+%29+%2F+%28+x+%2B+12+%29+=+.6+\"$
\n" ); document.write( " $\"+%28+12+%2B+2.4+%29+%2F+%28+12+%2B+12+%29+=+.6+\"$
\n" ); document.write( " $\"+14.4+%2F+24+=+.6+\"$
\n" ); document.write( " $\"+14.4+=+.6%2A24+\"$
\n" ); document.write( " $\"+14.4+=+14.4+\"$
\n" ); document.write( "OK \n" ); document.write( "

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