document.write( "Question 59261This question is from textbook Beginning Algebra
\n" ); document.write( ": Karen Waugtat investedsome money at 9% annual simple interest and $250 more than that amount at 10% annual interest.If her total yearly interest is $101,how much was invested in each rate. \n" ); document.write( "
Algebra.Com's Answer #40649 by checkley71(8403)\"\" \"About 
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.09X+.10(X+250)=101
\n" ); document.write( ".09X+.10X+25=101
\n" ); document.write( ".19X=101-25
\n" ); document.write( ".19X=76
\n" ); document.write( "X=76/.19
\n" ); document.write( "X=400 INVESTED @ 9%
\n" ); document.write( "400+250=650 INVESTED @ 10%
\n" ); document.write( "PROOF
\n" ); document.write( ".09*400+.10*650=101
\n" ); document.write( "36+65=101
\n" ); document.write( "101=101
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