document.write( "Question 59261This question is from textbook Beginning Algebra
\n" );
document.write( ": Karen Waugtat investedsome money at 9% annual simple interest and $250 more than that amount at 10% annual interest.If her total yearly interest is $101,how much was invested in each rate. \n" );
document.write( "
Algebra.Com's Answer #40649 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! .09X+.10(X+250)=101 \n" ); document.write( ".09X+.10X+25=101 \n" ); document.write( ".19X=101-25 \n" ); document.write( ".19X=76 \n" ); document.write( "X=76/.19 \n" ); document.write( "X=400 INVESTED @ 9% \n" ); document.write( "400+250=650 INVESTED @ 10% \n" ); document.write( "PROOF \n" ); document.write( ".09*400+.10*650=101 \n" ); document.write( "36+65=101 \n" ); document.write( "101=101 \n" ); document.write( " \n" ); document.write( " |