document.write( "Question 647891: The heights of 18-year-old men are approximately normally distributed with mean 68 inches and standard deviation 3 inches. What is the probability that the average height of a sample of ten 18-year-old men will be between 69 and 71 inches?
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document.write( "Answer
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document.write( " a. 0.8539
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document.write( " b. 0.2922
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document.write( " c. 0.3539
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document.write( " d. 0.1461
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document.write( " e. 0.1611\r
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document.write( "If you could please show me how to solve this problem. \n" );
document.write( "
Algebra.Com's Answer #406464 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! The heights of 18-year-old men are approximately normally distributed with mean 68 inches and standard deviation 3 inches. What is the probability that the average height of a sample of ten 18-year-old men will be between 69 and 71 inches? \n" ); document.write( "------- \n" ); document.write( "Note: The mean of the sample means is 68 \n" ); document.write( "The standard deviation of the sample means is 3/sqrt(10) \n" ); document.write( "---- \n" ); document.write( "z(69) = (69-68)/(3/sqrt(10)) = 1.0541 \n" ); document.write( "z(71) = (71-68)/(3/sqrt(10)) = 3.1623 \n" ); document.write( "--------------------------- \n" ); document.write( "P(69 < x-bar < 71) = P(1.0541 < z < 3.1623) = 0.1451 \n" ); document.write( "=================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "=================== \n" ); document.write( "Answer \n" ); document.write( "a. 0.8539 \n" ); document.write( "b. 0.2922 \n" ); document.write( "c. 0.3539 \n" ); document.write( "d. 0.1461 \n" ); document.write( "e. 0.1611 \n" ); document.write( " \n" ); document.write( " |