document.write( "Question 647907: It is an odd number.
\n" ); document.write( "The sum of the digits is 6.
\n" ); document.write( "The product of the digits is 9.
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Algebra.Com's Answer #406448 by stanbon(75887)\"\" \"About 
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It is an odd number.
\n" ); document.write( "The sum of the digits is 6.
\n" ); document.write( "The product of the digits is 9.
\n" ); document.write( "-------
\n" ); document.write( "I'm going to assum it is a 2-digit number:
\n" ); document.write( "Let the number be 10t + u
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\n" ); document.write( "Equations:
\n" ); document.write( "t + u = 6
\n" ); document.write( "tu = 9
\n" ); document.write( "-----
\n" ); document.write( "t = 6-u
\n" ); document.write( "---
\n" ); document.write( "(6-u)u = 9
\n" ); document.write( "6u-u^2 = 9
\n" ); document.write( "u^2 -6u + 9 = 0
\n" ); document.write( "Factor:
\n" ); document.write( "(u-3)(u-3) = 0
\n" ); document.write( "u = 3
\n" ); document.write( "---
\n" ); document.write( "Solve for \"t\":
\n" ); document.write( "t + u = 6
\n" ); document.write( "t + 3 = 6
\n" ); document.write( "t = 3
\n" ); document.write( "---
\n" ); document.write( "The number is 33
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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