document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=647838>Question 647838</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The second angle of a triangle measures twice as large as the first.  If the third angle measures 40 º more than the first, find the measures of all three angles. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #406422 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley79><B>checkley79(3341)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley79><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=406422\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You have x,2x (x+40) for the 3 angles.<BR>\n" );
document.write( "x+2x+x+40=180<BR>\n" );
document.write( "4x=180-40<BR>\n" );
document.write( "4x=140<BR>\n" );
document.write( "x=140/4<BR>\n" );
document.write( "x=35 degrees for tghe first angle<BR>\n" );
document.write( "2*35=70 degrees for the second angle.<BR>\n" );
document.write( "35+40=75 degrees for the third angle.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( "35+70+75=180<BR>\n" );
document.write( "180=180  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );