document.write( "Question 647801: a mother is presently 5 years older than twice her daughter's sge. 10 years ago the product of the mother and daughter's age was equal to 125.What is the mom's age? \n" ); document.write( "
Algebra.Com's Answer #406390 by stanbon(75887)\"\" \"About 
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a mother is presently 5 years older than twice her daughter's sge. 10 years ago the product of the mother and daughter's age was equal to 125.What is the mom's age?
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\n" ); document.write( "Equations:
\n" ); document.write( "m = 2d + 5
\n" ); document.write( "(m-10)(d-10) = 125
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\n" ); document.write( "Substitute for \"m\" and solve for \"d:
\n" ); document.write( "(2d+5-10)(d-10) = 125
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\n" ); document.write( "(2d-5)(d-10) = 125
\n" ); document.write( "2d^2-25d+50-125 = 0
\n" ); document.write( "---
\n" ); document.write( "2d^2 - 25d -75 = 0
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\n" ); document.write( "(d-15)(2d+5) = 0
\n" ); document.write( "d = 15 (daughter's age)
\n" ); document.write( "---
\n" ); document.write( "m = 2d+5 = 35 (mom's age)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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