document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=647790>Question 647790</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 5y-2(y-5)=19 what does y equal </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #406386 by </B><A HREF=/tutors/aboutme.mpl?userid=shweta><B>shweta(56)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=shweta><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=406386\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  5y -2(y-5)=19<BR>\n" );
document.write( " according to BODMAS rule, we will first open the bracket<BR>\n" );
document.write( " 5y -2y +10 =19     {{-2)*(-5); Here we are multiplying two negative number,so the  answer will be positive, +10}<BR>\n" );
document.write( " 3y +10 = 19<BR>\n" );
document.write( " Now subtract 10 from both the sides<BR>\n" );
document.write( " 3y +10 - 10 =19 -10       <BR>\n" );
document.write( "           <BR>\n" );
document.write( " 3y = 9              To get the value of 'y', we need to separate it from 3 but <BR>\n" );
document.write( "                     here 3 is neither added nor subtracted to 'y' ,rather it is <BR>\n" );
document.write( "                     multiplied to 'y'. In this case when we shift 3 to the <BR>\n" );
document.write( "                     opposite side of the 'equal to' sign ,it will be divided <BR>\n" );
document.write( "                     there.<BR>\n" );
document.write( "  y= 9/3<BR>\n" );
document.write( "  y= 3        </SPAN>\n" );
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