document.write( "Question 647714: The sum of two supplementary angles exceeds the difference of their measures by 116 degrees. Find the measures of each angle.
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #406346 by MathLover1(20849)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "supplementary angles, because they add up to \"180\"°\r
\n" ); document.write( "\n" ); document.write( "so, \"alpha%2Bbeta=180\"....1\r
\n" ); document.write( "\n" ); document.write( "so, \"alpha-beta\"....the difference\r
\n" ); document.write( "\n" ); document.write( "given: the sum of two supplementary angles \"exceeds\" the difference of their measures by \"116\" degrees.\r
\n" ); document.write( "\n" ); document.write( "\"alpha%2Bbeta=alpha-beta%2B116\"....2...solve for \"beta\"\r
\n" ); document.write( "\n" ); document.write( "\"cross%28alpha%29%2Bbeta=cross%28alpha%29-beta%2B116\"\r
\n" ); document.write( "\n" ); document.write( "\"beta=-beta%2B116\"\r
\n" ); document.write( "\n" ); document.write( "\"beta%2Bbeta=116\"\r
\n" ); document.write( "\n" ); document.write( "\"2%2Abeta=116\"\r
\n" ); document.write( "\n" ); document.write( "\"beta=116%2F2\"\r
\n" ); document.write( "\n" ); document.write( "\"beta=58\"\r
\n" ); document.write( "\n" ); document.write( "now find \"alpha\"\r
\n" ); document.write( "\n" ); document.write( "\"alpha%2Bbeta=180\"....1\r
\n" ); document.write( "\n" ); document.write( "\"alpha=180-beta\"\r
\n" ); document.write( "\n" ); document.write( "\"alpha=180-58\"\r
\n" ); document.write( "\n" ); document.write( "\"alpha=122\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );