document.write( "Question 647697: two angles are complementary. one angle is ten less than three times the other angle. find the measure of both angles. \n" ); document.write( "
Algebra.Com's Answer #406339 by shweta(56)![]() ![]() ![]() You can put this solution on YOUR website! Given :Two angles are complementary, means their sum is 90 degree.Let the two angles be a and b. \n" ); document.write( " a + b = 90 degree ......(1) \n" ); document.write( " It is given in the question that one angle is ten less than three times the other angle, say \n" ); document.write( " b = 10 less than 3* a( 3 times 'a' means 3 multiplied by a) \n" ); document.write( " b= 3*a - 10 ......(2) \n" ); document.write( " Now substitute the value of 'b'in (1) \n" ); document.write( " a + b = 90 \n" ); document.write( " a + 3*a- 10 = 90 ( coefficient of a is 1 ,so 1*a +3a= 4*a) \n" ); document.write( " 4*a = 90 + 10 \n" ); document.write( " 4*a =100 \n" ); document.write( " a = 100/4 \n" ); document.write( " a = 25 \n" ); document.write( " One angle 'a' is 40 degrees \n" ); document.write( " N ow to find the value of other angle 'b', put in the value of 'a' in the equation (2) \n" ); document.write( " b= 3*a - 10 \n" ); document.write( " b= 3*25 - 10 \n" ); document.write( " b= 75- 10 \n" ); document.write( " b= 65 degrees \n" ); document.write( " \n" ); document.write( " |