document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=647695>Question 647695</A>: <I><SPAN STYLE=\"word-break: break-all;\"> hi i needed to know how i would write this y= 4/5x-6 in the form ax+by+c=0 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #406337 by </B><A HREF=/tutors/aboutme.mpl?userid=DrBeeee><B>DrBeeee(684)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=DrBeeee><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=406337\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You sure can.<BR>\n" );
document.write( "Given<BR>\n" );
document.write( "(1) y = (4/5)*x - 6<BR>\n" );
document.write( "Subtract y from each side of the equation to get<BR>\n" );
document.write( "(2) y - y = (4/5)*x - 6 - y, or<BR>\n" );
document.write( "(3) 0 = (4/5)*x -y -6<BR>\n" );
document.write( "Now flip (3) around to obtain<BR>\n" );
document.write( "(4) 4/5x-y-6=0<BR>\n" );
document.write( "Compare to ax+by+c and you obtain<BR>\n" );
document.write( "a = 4/5<BR>\n" );
document.write( "b = -1<BR>\n" );
document.write( "c = -6 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );