document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=647687>Question 647687</A>: <I><SPAN STYLE=\"word-break: break-all;\"> y=sin(4x+pi/7)<BR>\n" );
document.write( "what is the phase shift </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #406336 by </B><A HREF=/tutors/aboutme.mpl?userid=DrBeeee><B>DrBeeee(684)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=DrBeeee><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=406336\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The phase shift is that value of x that makes the argument of the sine function equal to zero. In your case we have to solve for x when<BR>\n" );
document.write( "(1) 4*x + pi/7 = 0 or<BR>\n" );
document.write( "(2) x = - pi/28 rad<BR>\n" );
document.write( "or since pi rad = 180 deg we have<BR>\n" );
document.write( "(3) x = - 180/28 deg<BR>\n" );
document.write( "(4) x = -45/7 deg<BR>\n" );
document.write( "The phase shift is approximately -6.43 degrees. At this value of x you have sin(4x+pi/7) = o. That is, the sine wave crosses the x-axis at approx -6.43 degrees instead of at x = zero. Hence there is a shift of the sinwave to the left by 6.43 degrees. Get it? </SPAN>\n" );
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