document.write( "Question 647543: Professor I'm having trouble with solving absolute value equations and inequalities. Hopefully this is clear. /z-2/ > 0
\n" ); document.write( "(A) - infinity, +infinity. (B) 0 (C) 2,-2 or (D) - infinity, 2 and 2, infinity
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Algebra.Com's Answer #406284 by swincher4391(1107)\"\" \"About 
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\"abs%28z-2%29+%3E+0+\" = \"%28z-2%29+%3E0\" and \"-%28z-2%29+%3E+0\"
\n" ); document.write( "i)
\n" ); document.write( "\"z-2%3E0\"
\n" ); document.write( "\"z+%3E+2\"
\n" ); document.write( "ii)
\n" ); document.write( "\"-%28z-2%29%3E0\"
\n" ); document.write( "Recall when dividing or multiplying by a negative number, it switches the way the inequality points.
\n" ); document.write( "\"%28z-2%29%3C0\"
\n" ); document.write( "\"z%3C2\"\r
\n" ); document.write( "\n" ); document.write( "So we have that z<2 and z>2. The answer may be clearer if we put this in interval notation.\r
\n" ); document.write( "\n" ); document.write( "So z exists in (-infinity,2) U (2,infinity). U is the union of sets symbol.\r
\n" ); document.write( "\n" ); document.write( "D.
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