document.write( "Question 647530: Find the equation of the line containing the point (3,5) and parallel to the line x+3y=9 \n" ); document.write( "
Algebra.Com's Answer #406276 by swincher4391(1107)\"\" \"About 
You can put this solution on YOUR website!
In order to do point-slope form, we need a point and a slope. (Nice name right?)\r
\n" ); document.write( "\n" ); document.write( "We have a point, let's get ourselves a slope.\r
\n" ); document.write( "\n" ); document.write( "We are given a vital piece of information. Our line must be parallel to this one: x+3y=9. This means they must have the same slope. \r
\n" ); document.write( "\n" ); document.write( "If you're clever, you may know that of the form Ax+By=C, the slope is -A/B or -1/3. Otherwise, just solve for y=mx+b form and m is your slope. \r
\n" ); document.write( "\n" ); document.write( "3y = 9-x
\n" ); document.write( "y = 9/3 - x/3
\n" ); document.write( "y = 3 - (1/3)x\r
\n" ); document.write( "\n" ); document.write( "And as we predicted, our slope is -1/3.\r
\n" ); document.write( "\n" ); document.write( "Now we have a point and a slope.
\n" ); document.write( "m=-1/3
\n" ); document.write( "(x1,y1) = (3,5)\r
\n" ); document.write( "\n" ); document.write( "\"%28y-y1%29+=+m%2A%28x-x1%29\"
\n" ); document.write( "\"%28y-5%29+=+%28-1%2F3%29%28x-3%29\"
\n" ); document.write( "\"y-5+=+%28-1%2F3%29%2Ax+%2B+1\"
\n" ); document.write( "\"highlight%28y+=+%28-1%2F3%29x+%2B+6%29\"\r
\n" ); document.write( "\n" ); document.write( "Hope this helps!\r
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