document.write( "Question 647495: Find the distance between the following points.
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Algebra.Com's Answer #406234 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "Note: is the first point . So this means that \"x%5B1%5D=8\" and \"y%5B1%5D=5\".\r
\n" ); document.write( "\n" ); document.write( "Also, is the second point . So this means that \"x%5B2%5D=0\" and \"y%5B2%5D=20\".\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%28%28x%5B1%5D-x%5B2%5D%29%5E2%2B%28y%5B1%5D-y%5B2%5D%29%5E2%29\" Start with the distance formula.\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%28%288-0%29%5E2%2B%285-20%29%5E2%29\" Plug in \"x%5B1%5D=8\", \"x%5B2%5D=0\", \"y%5B1%5D=5\", and \"y%5B2%5D=20\".\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%28%288%29%5E2%2B%285-20%29%5E2%29\" Subtract \"0\" from \"8\" to get \"8\".\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%28%288%29%5E2%2B%28-15%29%5E2%29\" Subtract \"20\" from \"5\" to get \"-15\".\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%2864%2B%28-15%29%5E2%29\" Square \"8\" to get \"64\".\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%2864%2B225%29\" Square \"-15\" to get \"225\".\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%28289%29\" Add \"64\" to \"225\" to get \"289\".\r
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\n" ); document.write( "\n" ); document.write( "\"d=17\" Take the square root of \"289\" to get \"17\".\r
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\n" ); document.write( "\n" ); document.write( "So our answer is \"d=17\" \r
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\n" ); document.write( "\n" ); document.write( "So the distance between the two points is 17 units. \r
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