document.write( "Question 647424: If PQ=7 and QR=10, then PR=? \n" ); document.write( "
Algebra.Com's Answer #406185 by checkley79(3341)\"\" \"About 
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If PQ=7 and QR=10, then PR=?
\n" ); document.write( "PQ=7 divide by Q
\n" ); document.write( "P=7/Q\r
\n" ); document.write( "\n" ); document.write( "QR=10 divide by Q
\n" ); document.write( "R=10/Q\r
\n" ); document.write( "\n" ); document.write( "PR=(7/Q)(10/Q) multiply numerators & denominators.
\n" ); document.write( "PR=70/Q^2 ANS.
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