document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=647385>Question 647385</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One side of a rectangle is 6 feet long and the diagonal is 14 feet long.  Find the length of the other side of the rectangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #406167 by </B><A HREF=/tutors/aboutme.mpl?userid=Sarpi><B>Sarpi(32)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Sarpi><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Sarpi><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=406167\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A diagonal line divides the rectangle in two shape of \"right-angle triangle\"<BR>\n" );
document.write( "So the diagonal = 'hypotenuse' of the right-angle triangle = 14ft<BR>\n" );
document.write( "and the width = the 'opposite' of the right-angle triangle = 6ft (that is taking into account down part of the rectangle after dividing it)\r<BR>\n" );
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document.write( "Now, the question becomes a problem of trigonometry - 'square of hypotenuse' is equal to 'sum square of both the opposite and the adjacent'; <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=H%5E2+=+O%5E2+%2B+A%5E2 ALIGN=MIDDLE  ALT=\"H%5E2+=+O%5E2+%2B+A%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "=> H = 14ft, O = 6ft and we look for A<BR>\n" );
document.write( "=> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=H%5E2+=+O%5E2+%2B+A%5E2 ALIGN=MIDDLE  ALT=\"H%5E2+=+O%5E2+%2B+A%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=14%5E2+=+6%5E2+%2B+A%5E2 ALIGN=MIDDLE  ALT=\"14%5E2+=+6%5E2+%2B+A%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=196+=+36+%2B+A%5E2 ALIGN=MIDDLE  ALT=\"196+=+36+%2B+A%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=196+-+36+=+A%5E2 ALIGN=MIDDLE  ALT=\"196+-+36+=+A%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=160+=+A%5E2 ALIGN=MIDDLE  ALT=\"160+=+A%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Then by taking square root of  both sides: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A%5E2 ALIGN=MIDDLE  ALT=\"A%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > will become 'A' and 160 will be <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%28160%29 ALIGN=MIDDLE  ALT=\"sqrt%28160%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "=> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%28160%29+=+A ALIGN=MIDDLE  ALT=\"sqrt%28160%29+=+A\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=12.649+=+A ALIGN=MIDDLE  ALT=\"12.649+=+A\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Hence, A = 12.649, so approximately the length of the other side is 12.6ft<BR>\n" );
document.write( " </SPAN>\n" );
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