document.write( "Question 59268: PLEASE help me to find tables of value;\r
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document.write( "y=x^2+3x-3 \n" );
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Algebra.Com's Answer #40616 by uma(370)![]() ![]() ![]() You can put this solution on YOUR website! Given y = x^2 + 3x - 3\r \n" ); document.write( "\n" ); document.write( "To find the table of values, we subtitute different values for x and find the corresponding values for y.\r \n" ); document.write( "\n" ); document.write( "(i) when x = 0\r \n" ); document.write( "\n" ); document.write( "Plugging in this in the above we have..\r \n" ); document.write( "\n" ); document.write( "y = 0 + 0 - 3\r \n" ); document.write( "\n" ); document.write( "Therefore (0, -3) is an ordered pair\r \n" ); document.write( "\n" ); document.write( "(ii) When x = 1,\r \n" ); document.write( "\n" ); document.write( "y = 1^2 + 3(1) - 3\r \n" ); document.write( "\n" ); document.write( "= 1 + 3 - 3\r \n" ); document.write( "\n" ); document.write( "= 1\r \n" ); document.write( "\n" ); document.write( "So (1,1) is another pair.\r \n" ); document.write( "\n" ); document.write( "Thus for different vslues of x, we get different values for y.\r \n" ); document.write( "\n" ); document.write( "Good Luck!!! \n" ); document.write( " |