document.write( "Question 647364: Hi, I'm in a hybrid math class at my college, so i don't get to see my teacher for another week and i have no idea how to do this problem. Can you please help me?
\n" ); document.write( " I don't understand the \"K\" rule:
\n" ); document.write( " K={K if K>(or equal to)0
\n" ); document.write( " {-K if K< 0
\n" ); document.write( "I have an example from my book here: (I am just having a hard time with this because my book does not explain anything.)
\n" ); document.write( " absol. (x-2)^2 absol.
\n" ); document.write( "I thought you would do this: (x-2)(x-2) and multiply: x^2+4
\n" ); document.write( "The answer in the book says (x-2)^2 is the answer along with: absol.K absol.=K if K> (or equal to) 0
\n" ); document.write( "I dont understand how to find out what K rule to use if there is no real number value.\r
\n" ); document.write( "\n" ); document.write( "Thank you,
\n" ); document.write( "Sydney \n" ); document.write( "

Algebra.Com's Answer #406148 by ewatrrr(24785) $\"\"$ $\"About$

You can put this solution on YOUR website!

 
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document.write( "Hi,
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document.write( "the idea is by definition: absolute value |number|  ALWAYS has an 'absolutely' ≥ 0  result
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document.write( "regardless if the number is positive or negative
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document.write( "for ex:  |4| = 4  and |-4| = 4
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document.write( "As to:
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document.write( " |K| = K, that would only be true if K itself were ≥ 0\r
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document.write( "|(x-2)^2| = (x-2)^2     | quanity (x-2) 'squared' is ALWAYS ≥ 0
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