document.write( "Question 647299: If log[16]x+log[4]x+log[2]x=7, then x=???
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Algebra.Com's Answer #406107 by ewatrrr(24785)\"\" \"About 
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document.write( "Hi,
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document.write( "log[16]x+log[4]x+log[2]x=7
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document.write( "Note: \"log%2816%2Cx%29+=+log%282%2Cx%29%2Flog%282%2C16%29=+log%282%2Cx%29%2F4\" &\"log%284%2Cx%29+=+log%282%2Cx%29%2Flog%282%2C4%29=+log%282%2Cx%29%2F2\"
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document.write( "\"log%282%2Cx%29%2F4+%2B+log%282%2Cx%29%2F2+%2B+log%282%2Cx%29+=+7\" |Multiplying thru by 28 so as all denominators = 1
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document.write( " \"49%2Alog%282%2Cx%29+=+196\"
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document.write( "  \"log%282%2Cx%29+=+4\"
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document.write( "   \"2%5E4+=+x+=+16\" \n" );
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