document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=646300>Question 646300</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solve the following logarithmic equation. \r<BR>\n" );
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document.write( "log(4x+7)=1+log(x-6)\r<BR>\n" );
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document.write( "x=?\r<BR>\n" );
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document.write( "please show all work!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #406096 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=406096\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> solve the following logarithmic equation. <BR>\n" );
document.write( "log(4x+7)=1+log(x-6)<BR>\n" );
document.write( "log(4x+7)-log(x-6)=1<BR>\n" );
document.write( "log[(4x+7)/(x-6)]=1<BR>\n" );
document.write( "convert to exponential form:base10) raised to log of number(1)=number(4x+7)/(x-6)<BR>\n" );
document.write( "10^1=(4x+7)/(x-6)=10<BR>\n" );
document.write( "4x+7=10(x-6)<BR>\n" );
document.write( "4x+7=10x-60<BR>\n" );
document.write( "6x=67<BR>\n" );
document.write( "x=67/6<BR>\n" );
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