document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=647227>Question 647227</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the length of a rectangle is 6 ft longer than its width and the rectangle has a perimeter of 36 ft than what is its area? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #406064 by </B><A HREF=/tutors/aboutme.mpl?userid=colliefan><B>colliefan(242)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=colliefan><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=406064\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> width is w<BR>\n" );
document.write( "length is w+6\r<BR>\n" );
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document.write( "The perimeter is 2 times the width plus 2 times the length and equals 36 so:<BR>\n" );
document.write( "2w + 2(w+6) = 36<BR>\n" );
document.write( "2w + 2w + 12 =36<BR>\n" );
document.write( "4w +12 = 36<BR>\n" );
document.write( "4w + 12 -12 = 36-12<BR>\n" );
document.write( "4w+0 = 24<BR>\n" );
document.write( "4w =24<BR>\n" );
document.write( "4w/4 = 24/4<BR>\n" );
document.write( "w=6\r<BR>\n" );
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document.write( "If w = 6, then l must be 12.\r<BR>\n" );
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document.write( "Substitute back into the original equation to make sure it is correct.\r<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );