document.write( "Question 647240: find the focus and directrix
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\n" ); document.write( "\n" ); document.write( "9x^2=4y
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Algebra.Com's Answer #406050 by aaronwiz(69)\"\" \"About 
You can put this solution on YOUR website!
Hi, my name is Aaron I am in 10th grade and im in honors trig/pre-calc.\r
\n" ); document.write( "\n" ); document.write( "I do not feel like showing all the work, because I have lots of HW to do. However I will guide you, and provide an answer.\r
\n" ); document.write( "\n" ); document.write( "First put it in the correct form, (x-h)^2=4p(y-k) we know the vertex is at (0,0) so \r
\n" ); document.write( "\n" ); document.write( "it turns out being already in the correct form. \r
\n" ); document.write( "\n" ); document.write( "As you can see the coef. of y represents the \"4p.\" Thus 4=4p\r
\n" ); document.write( "\n" ); document.write( "Since the graph opens up, and p=1, we know the focus is one unit above the vertex (0,1)\r
\n" ); document.write( "\n" ); document.write( "Also since p=1 we know the directrix is one unit below the vertex, y=-1 is the equation for it.\r
\n" ); document.write( "\n" ); document.write( "hope I helped
\n" ); document.write( "-Aaron
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