document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=647192>Question 647192</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two squares are such that the perimeter of one square is 24 greater than the other.  If the sum of the areas of the squares is 596 square units, find the perimeter of the larger square.\r<BR>\n" );
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document.write( "This is what I got so far: square A perimeter = x+x+x+x +24 or 4x +24 - simplified x+6.  Area of square B (x+6) squared = 596<BR>\n" );
document.write( "(x+6)???? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #406035 by </B><A HREF=/tutors/aboutme.mpl?userid=aaronwiz><B>aaronwiz(69)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=aaronwiz><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=406035\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hi, my name is Aaron I am in 10th grade and im in honors trig/pre-calc.\r<BR>\n" );
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document.write( "Lets call a side of square A (the smaller square) X.<BR>\n" );
document.write( "Lets call a side of square b (the bigger square) Y.\r<BR>\n" );
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document.write( "Lets set up a system of equations.\r<BR>\n" );
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document.write( "Since we know one side of square B is 6 bigger, we can say\r<BR>\n" );
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document.write( "x+6=y\r<BR>\n" );
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document.write( "also we know the area of them added together is 596\r<BR>\n" );
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document.write( "x^2+y^2=596\r<BR>\n" );
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document.write( "substitute y=x+6 into the equation above\r<BR>\n" );
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document.write( "x^2+ (x+6)^2=596\r<BR>\n" );
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document.write( "foil...\r<BR>\n" );
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document.write( "x^2+x^2 +12x+36=596\r<BR>\n" );
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document.write( "simplify it down\r<BR>\n" );
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document.write( "2x^2+12x=560<BR>\n" );
document.write( "x^2+6x-280=0\r<BR>\n" );
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document.write( "now plug into quadratic formula\r<BR>\n" );
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document.write( "result: x= 14 or-20\r<BR>\n" );
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document.write( "since distance cant be positive x has to be 14. we now know the sides of square A is 14\r<BR>\n" );
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document.write( "so plug back into y=x+6 to find the side length of square b\r<BR>\n" );
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document.write( "y=20\r<BR>\n" );
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document.write( "multiply by 4, because a square has 4 sides, so we can find permitter. \r<BR>\n" );
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document.write( "Square B's permitter is 80units.\r<BR>\n" );
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document.write( "Hope this helped. Please leave me positive feedback, this took over 20 mins to type </SPAN>\n" );
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