document.write( "Question 647149: five times my age in 2 years is 100. How old am I? \n" ); document.write( "
Algebra.Com's Answer #406032 by colliefan(242)\"\" \"About 
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Algebraically:\r
\n" ); document.write( "\n" ); document.write( "If my age is x, my age in 2 years can be represented as x+2\r
\n" ); document.write( "\n" ); document.write( "Then:
\n" ); document.write( "5(x+2)=100
\n" ); document.write( "5x+10=100
\n" ); document.write( "5x+10-10=100-10
\n" ); document.write( "5x+0=90
\n" ); document.write( "5x=90
\n" ); document.write( "5x/5=90/5
\n" ); document.write( "x*1=18
\n" ); document.write( "x=18\r
\n" ); document.write( "\n" ); document.write( "Substitute this value back into the original equation to make sure it is correct.
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