document.write( "Question 647177: -2/3(6/5x-7/10)= 17/20 \n" ); document.write( "
Algebra.Com's Answer #406024 by aaronwiz(69) ![]() You can put this solution on YOUR website! Hi, my name is Aaron I am in 10th grade and im in honors trig/pre-calc. It seems you have a mean teacher seeing she gave you such wacky fractions to deal with\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Start by distributing the -2/3 to every term in the parentheses. \r \n" ); document.write( "\n" ); document.write( "it should simplify down to -4/5x+7/15=17/20\r \n" ); document.write( "\n" ); document.write( "isolate x... \n" ); document.write( "-4/5x=17/20-7/15 \n" ); document.write( "-4/5x=51/60-28/60 \n" ); document.write( "-4/5x=23/60\r \n" ); document.write( "\n" ); document.write( "multiply both sides by the recepericol of the coef. of x\r \n" ); document.write( "\n" ); document.write( "(-5/4)*-4/5x=23/60(-5/4) \n" ); document.write( "x=-23/48 \n" ); document.write( " |