document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=646662>Question 646662</A>: <I><SPAN STYLE=\"word-break: break-all;\"> what is the areaa of 4in dia and 10 ft long pipe </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #405912 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=405912\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> what is the areaa of 4in dia and 10 ft long pipe<BR>\n" );
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document.write( "r = 2 in<BR>\n" );
document.write( "h = 120 inches<BR>\n" );
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document.write( "The area of each end is pi*r^2 = 4pi sq inches.<BR>\n" );
document.write( "The lateral area = 2pi*r*h<BR>\n" );
document.write( "LA = 2pi*2*120 sq inches<BR>\n" );
document.write( "= 480pi sq inches IF the 4 inches the OD of the pipe. </SPAN>\n" );
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