document.write( "Question 645972: Could you show me how to simplify the expression 2^(x+1)=6^(x-1) using logarithmic principles \n" ); document.write( "

Algebra.Com's Answer #405802 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

You can put this solution on YOUR website!
2^(x+1) = 6^(x-1)
\n" ); document.write( " $\"log%282%5E%28x%2B1%29%29+=+log%286%5E%28x-1%29%29\"$
\n" ); document.write( ":
\n" ); document.write( "using the log equiv of exponents
\n" ); document.write( "(x+1)*log(2) = (x-1)*log(6)
\n" ); document.write( ":
\n" ); document.write( "Find the logs of 2 and 6; then just basic algebra
\n" ); document.write( ".301(x+1) = .778(x-1)
\n" ); document.write( ".301x + .301 = .778x - .778
\n" ); document.write( ".301 + .778 = .778x - .301x
\n" ); document.write( "1.079 = .477x
\n" ); document.write( "x = 1.079/.477
\n" ); document.write( "x = 2.262
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "You can confirm this on your calc,
\n" ); document.write( "enter 2^(2.262+1) results: 9.593
\n" ); document.write( "enter 6^(2.261-1) results: 9.594 (logs are not exact) \n" ); document.write( "

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