document.write( "Question 646174: According to the Internal Revenue Service, the mean tax for the year 2011
\n" ); document.write( "was $3,000. Assume the standard deviation is $410 and that the amounts follow
\n" ); document.write( "a normal probability distribution.
\n" ); document.write( "What percent of the refunds are less than $2,900 or greater than $3,200?
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Algebra.Com's Answer #405777 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi,
\n" ); document.write( "mean tax for the year 2011 was $3,000. Assume the standard deviation is $410
\n" ); document.write( "Using TI-83 Calculator to Probability Distribution Values Normal
\n" ); document.write( "Press 2nd VARS [DISTR].Scroll down to 2:normalcdf and Press ENTER.
\n" ); document.write( "Enter data and Press ENTER.
\n" ); document.write( " P(x < 2900 or > 3200) = 1 - P(2900 ≤ x ≤ 3200)
\n" ); document.write( " = 1- normalcdf(2900, 3200, 3000, 410)
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