document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=646132>Question 646132</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need to create a linear equation that shows how old I will be when I am 3 times my daughters age. Currently, I am 45 to her 11 and I was 34 when she was born. For some reason this math escapes me and if possible I would like each step explained so that I will be able to do the next one without help (high expectations on my part). I appreciate any help that you can offer.<BR>\n" );
document.write( "Lisa  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #405741 by </B><A HREF=/tutors/aboutme.mpl?userid=MathTherapy><B>MathTherapy(10552)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=MathTherapy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=MathTherapy><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=405741\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "I need to create a linear equation that shows how old I will be when I am 3 times my daughters age. Currently, I am 45 to her 11 and I was 34 when she was born. For some reason this math escapes me and if possible I would like each step explained so that I will be able to do the next one without help (high expectations on my part). I appreciate any help that you can offer.<BR>\n" );
document.write( "Lisa \r<BR>\n" );
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document.write( "Let the age that you will be when you're 3 times your daughter's age be A.<BR>\n" );
document.write( "Since you're currently 45 and she's currently 11, a 34-year age difference exists. This means that your daughter will always be 34 years younger than you, which also means that when you're A years-old, she will be (A - 34) years-old. \r<BR>\n" );
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document.write( "This means that the age that you will be when you're 3 times your daughter's age, equals 3 times your daughter's age then, or algebraically:\r<BR>\n" );
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document.write( "A = 3(A - 34)<BR>\n" );
document.write( "A = 3A - 102<BR>\n" );
document.write( "A - 3A = - 102<BR>\n" );
document.write( "- 2A = - 102\r<BR>\n" );
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document.write( "A, or age that you will be when you're 3 times your daughter's age = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28-+102%29%2F-+2 ALIGN=MIDDLE  ALT=\"%28-+102%29%2F-+2\"   DISABLED_style= \"max-width:90%; height:auto;\" >, or <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight_green%2851%29 ALIGN=MIDDLE  ALT=\"highlight_green%2851%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Check<BR>\n" );
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document.write( "Your age then (51) will be 3 times your daughter's age then (A - 34, or 51 - 34, or 17)\r<BR>\n" );
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document.write( "51 = 3(17)\r<BR>\n" );
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document.write( "51 = 51 (TRUE)\r<BR>\n" );
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document.write( "Send comments and “thank-yous” to “D” at MathMadEzy@aol.com  </SPAN>\n" );
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