document.write( "Question 646101: The weights of adult Asian palm civets are known to be normally distributed with
\n" ); document.write( "a mean of 7.7 pounds and a standard deviation of 0.95 pounds. What is the
\n" ); document.write( "probability that a randomly selected civet will:\r
\n" ); document.write( "\n" ); document.write( "A. Weigh at least 6 pounds?
\n" ); document.write( "B. Weigh less than 5 pounds or more than 10 pounds?\r
\n" ); document.write( "\n" ); document.write( "Please help, i'm so confused! thank you
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Algebra.Com's Answer #405730 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi,
\n" ); document.write( "mean of 7.7 pounds and a standard deviation of 0.95 pounds
\n" ); document.write( "Using TI-83 Calculator to Compute Normal Probability Distribution Values:
\n" ); document.write( "Press 2nd VARS [DISTR].Scroll down to 2:normalcdf and Press ENTER:
\n" ); document.write( "Enter proper values, Press ENTER.
\n" ); document.write( "P(Weigh at least 6 pounds) is normalcdf(6,9999,7.7,.95)
\n" ); document.write( "Note: The 9999 is used as the larger value to be at least 5 standard deviations from the mean.
\n" ); document.write( "P(Weigh less than 5 pounds or more than 10 pounds) = 1 - P(5 ≤ x ≤ 10)
\n" ); document.write( " = 1 - normalcdf(5,10,7.7,.95) \n" ); document.write( "
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