document.write( "Question 646102: Solve the equation using factoring techniques
\n" ); document.write( "25x^4(fourth power)-401x^2(second power)+16=0 \n" ); document.write( "

Algebra.Com's Answer #405729 by MathLover1(20850) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"25x%5E4-401x%5E2%2B16=0\"$ ......replace $\"-401x%5E2\"$ with $\"-x%5E2-400x%5E2\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"25x%5E4-x%5E2-400x%5E2%2B16=0\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"25x%5E4-400x%5E2+-x%5E2+%2B16=0\"$ .....group\r
\n" ); document.write( "\n" ); document.write( " $\"%2825x%5E4-400x%5E2%29+-%28x%5E2+-16%29=0\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"25x%5E2%28x%5E2-16%29+-%28x%5E2+-16%29=0\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"%28x%5E2-16%29%2825x%5E2-1%29=0\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"%28x%5E2-4%5E2%29%28%285x%29%5E2-1%29=0\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"%28x-4%29%28x%2B4%29%285x-1%29%285x%2B1%29=0\"$ \r
\n" ); document.write( "\n" ); document.write( "solutions:\r
\n" ); document.write( "\n" ); document.write( "if
\n" ); document.write( " $\"%28x-4%29=0\"$ .......=>... $\"x=4\"$ \r
\n" ); document.write( "\n" ); document.write( "if
\n" ); document.write( " $\"%28x%2B4%29=0\"$ .......=>... $\"x=-4\"$ \r
\n" ); document.write( "\n" ); document.write( "if
\n" ); document.write( " $\"%285x-1%29=0\"$ .......=>... $\"5x=1\"$ =>... $\"x=1%2F5\"$ \r
\n" ); document.write( "\n" ); document.write( "if
\n" ); document.write( " $\"%285x%2B1%29=0\"$ .......=>... $\"5x=-1\"$ =>... $\"x=-1%2F5\"$ \r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

\n" );