document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=59154>Question 59154</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Martina leaves home at 9 A.M., bicycling at a rate of 24 mi/h.  Two hours later, John leaves, driving at the rate of 48 mi/h.  At what time will John catch up with Martina? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #40566 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=40566\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 24X=48(X-2)<BR>\n" );
document.write( "24X=48X-96<BR>\n" );
document.write( "24X-48X=-96<BR>\n" );
document.write( "-24X=-96<BR>\n" );
document.write( "X=-96/-24<BR>\n" );
document.write( "X=4 HOURS JOHN WILL CATCH UP WITH MARTINA. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );