document.write( "Question 645738: A box contains nickels, dimes, and quarters worth $2.00.Find all possibilities for the number of each coin if there are three more dimes than quarters. \n" ); document.write( "
Algebra.Com's Answer #405603 by solver91311(24713)![]() ![]() You can put this solution on YOUR website! \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The problem says, \"nickels, dimes, and quarters\"; all plural, hence there must be at least 2 of any of them.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If there are 2 quarters, then there are 5 dimes making $1.00, so there are 20 nickels.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If there are 3 quarters, then there are 6 dimes making $1.35, so there are 13 nickels.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If there are 4 quarters, then there are 7 dimes making $1.70, so there are 6 nickels.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If there are 5 quarters, then there are 8 dimes making $2.05 -- oops! Too much.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Hence there are exactly three possibliities, 2, 3, or 4 quarters and the resulting number of dimes and nickels.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "John \n" ); document.write( " \n" ); document.write( "My calculator said it, I believe it, that settles it \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |