document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=49056>Question 49056</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am not sure how to go about changing the following problem into standard form.  I tried to do completing the square, but I'm not sure how to use it in this situation or when there is a coefficient other than 1 in front of x^2 and y^2.  I would greatly appreciate help on how to solve the following problem.  Thanks!\r<BR>\n" );
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document.write( "Change the equation to standard form and name the figure.\r<BR>\n" );
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document.write( "3x^2-2y^2-12x-20y-44=0<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #40552 by </B><A HREF=/tutors/aboutme.mpl?userid=xerxes0212><B>xerxes0212(2)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=xerxes0212><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=40552\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">    3x^2 - 2y^2 - 12x - 20y - 44 = 0<BR>\n" );
document.write( "Transpose -44 to the other side.<BR>\n" );
document.write( "   3x^2 - 2y^2 - 12x - 20y = 44<BR>\n" );
document.write( "Rearrange the terms.<BR>\n" );
document.write( "   3x^2 - 12x - 2y^2 - 20y = 44<BR>\n" );
document.write( "Factor expressions with same variables by finding the common factor.<BR>\n" );
document.write( "   3(x^2 - 4x) - 2(y^2 + 10y) = 44<BR>\n" );
document.write( "Use completing the squares and balance the equation (add terms to the right side) by adding the terms that were added to the left side.<BR>\n" );
document.write( "   3(x^2 - 4x + 4) - 2(y^2 + 10y + 25) = 44 + 3(4) - 2(25)<BR>\n" );
document.write( "Simplify the right side.<BR>\n" );
document.write( "   3(x^2 - 4x + 4) - 2(y^2 + 10y + 25) = 6<BR>\n" );
document.write( "Write the perfect square trinomials as square of binomials.<BR>\n" );
document.write( "   3(x - 2)^2 - 2(y+ 5)^2 = 6<BR>\n" );
document.write( "Make the right side equal to 1 by dividing all terms by 6.<BR>\n" );
document.write( " (x - 2)^2 - (y + 5)^2 <BR>\n" );
document.write( " ---------   ---------  = 1<BR>\n" );
document.write( "     2     3\r<BR>\n" );
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document.write( "This equation represents a hyperbola with vertical traverse axis. </SPAN>\n" );
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