document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=645408>Question 645408</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 2nd # is 7 times the first #.  third number is 100 more than the first #. If the sum of the three numbers is 442, find the numbers.<BR>\n" );
document.write( "please show me HOW you get the answer as well as the answer.<BR>\n" );
document.write( "thank you  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #405494 by </B><A HREF=/tutors/aboutme.mpl?userid=sachi><B>sachi(548)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sachi><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=sachi><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=405494\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the 2nd no is x<BR>\n" );
document.write( "than 1st=7x<BR>\n" );
document.write( "& 3rd=x+100<BR>\n" );
document.write( "so x+7x+x+100=442<BR>\n" );
document.write( "or 9x=442-100=342<BR>\n" );
document.write( "or x=38<BR>\n" );
document.write( "so the nos are 38,266,138<BR>\n" );
document.write( "ans </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );