document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=643626>Question 643626</A>: <I><SPAN STYLE=\"word-break: break-all;\"> At a national computer show, two software companies continuously run videos showing their products. Company  A's video repeats every 33 minutes, while Company B's video repeats every 6 minutes. If both companies begain the videos at 1:00pm when the show opens, how many mnutes will elapse before they are in sync again? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #405449 by </B><A HREF=/tutors/aboutme.mpl?userid=htmentor><B>htmentor(1343)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=htmentor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=htmentor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=405449\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Company A's video repeats every 33 mins.<BR>\n" );
document.write( "Company B's vidoe repeats every 6 mins.<BR>\n" );
document.write( "They will be in sync when the number of minutes passed is equal to the LCM between 6 and 33.<BR>\n" );
document.write( "The LCM = (2x3)(3x11)/3 = 6x11 = 66<BR>\n" );
document.write( "So the videos will sync at 2:06 pm<BR>\n" );
document.write( "Video B will have played 11 times (11x6 mins) and video A will have played twice (2x33 mins) when they sync up again </SPAN>\n" );
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