document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=645364>Question 645364</A>: <I><SPAN STYLE=\"word-break: break-all;\"> umhh another problem sir, hehe I gone crazy just to solve this problem but still I can't solve it. Can you help me??  The problem goes like this:     \"One pipe can fill a pool 1.25 times faster than a second pipe. When both pipes are opened, they fill the pool in five hours. How long would it take to fill the pool if only the slower piped is used?\"       Thank you so much!!! :D<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #405439 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=405439\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> One pipe can fill a pool 1.25 times faster than a second pipe. When both pipes are opened, they fill the pool in five hours. How long would it take to fill the pool if only the slower piped is used?<BR>\n" );
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document.write( "Let s = time (hours) it takes for slower pipe to fill alone<BR>\n" );
document.write( "then<BR>\n" );
document.write( "1.25s = time (hours) for faster pipe alone<BR>\n" );
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document.write( "5(1/s + 1/(1.25s)) = 1<BR>\n" );
document.write( "multiply both sides by 1.25s to get:<BR>\n" );
document.write( "5(1.25 + 1) = 1.25s<BR>\n" );
document.write( "5(2.25) = 1.25s<BR>\n" );
document.write( "11.25 = 1.25s<BR>\n" );
document.write( "11.25/1.25 = s<BR>\n" );
document.write( "9 hours = s </SPAN>\n" );
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