document.write( "Question 644729: I am having troubles solving this algebraically, must give exact solutions, the equation is: 2cos^2x + 3cosx +1 =0 \n" ); document.write( "

Algebra.Com's Answer #405438 by lwsshak3(11628) $\"\"$ $\"About$

You can put this solution on YOUR website!
For [0,π], solve for x
\n" ); document.write( "2cos^2x + 3cosx +1 =0
\n" ); document.write( "(2cosx+1)(cosx+1)=0
\n" ); document.write( "2cosx+1=0
\n" ); document.write( "cosx=-1/2
\n" ); document.write( "x=2π/3
\n" ); document.write( "or
\n" ); document.write( "cosx+1
\n" ); document.write( "cosx=-1
\n" ); document.write( "x=π
\n" ); document.write( " \n" ); document.write( "

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