document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=645334>Question 645334</A>: <I><SPAN STYLE=\"word-break: break-all;\"> i am going to be real honest i am in collage, however i can not remember how to take this problem and turn it into the lowest form 6/7 divided 1/5 maybe you can help show me how  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #405435 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=405435\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 6/7 divided 1/5<BR>\n" );
document.write( "change from a division to a multiplication by flipping the right term:<BR>\n" );
document.write( "6/7 multiply 5/1<BR>\n" );
document.write( "6/7 * 5/1<BR>\n" );
document.write( "(6*5)/(7*1)<BR>\n" );
document.write( "30/7 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );