document.write( "Question 645148: It takes 3 pumps 8 hours to pump water out of a flooded basement. Find the time it takes each of them to pump water out of the basement by itself if it is known that the first pump is
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document.write( "twice as fast as the second pimp and three times as fast as the third pump. \n" );
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Algebra.Com's Answer #405410 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! It takes 3 pumps 8 hours to pump water out of a flooded basement. \n" ); document.write( " Find the time it takes each of them to pump water out of the basement by \n" ); document.write( " itself if it is known that the first pump is twice as fast as the second \n" ); document.write( " pimp and three times as fast as the third pump. \n" ); document.write( ": \n" ); document.write( "I am not sure how effective a pimp would be in this task. \n" ); document.write( ": \n" ); document.write( "Three pumps with times of: a, b, c \n" ); document.write( "Let the completed job = 1 (an empty basement) \n" ); document.write( ": \n" ); document.write( "Write a shared work equation \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "\"the first pump is twice as fast as the second\" \n" ); document.write( "b = 2a (b take 2 times as long as a) \n" ); document.write( ": \n" ); document.write( "three times as fast as the third pump. \n" ); document.write( "c = 3a (c takes 3 times as long as a) \n" ); document.write( ": \n" ); document.write( "Replace b and c in the shared work equation \n" ); document.write( " \n" ); document.write( "Multiply by 6a to clear the denominators, results: \n" ); document.write( "6(8) + 3(8) + 2(8) = 6a \n" ); document.write( "48 + 24 + 16 = 6a \n" ); document.write( "88 = 6a \n" ); document.write( "a = 88/6 \n" ); document.write( "a = 14 \n" ); document.write( "then \n" ); document.write( "b = 2(14 \n" ); document.write( "and \n" ); document.write( "c = 3(14 |