document.write( "Question 645258: How do I go about solving this problem. The longer leg of a right triangle is 1 meter longer than the shorter leg. The hypotenuse is 1 meter than twice the shorter leg. Find the lenvth of the shorter leg of the triangle. \n" ); document.write( "
Algebra.Com's Answer #405407 by stanbon(75887)\"\" \"About 
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How do I go about solving this problem. The longer leg of a right triangle is 1 meter longer than the shorter leg. The hypotenuse is 1 meter less than twice the shorter leg. Find the lenvth of the shorter leg of the triangle.
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\n" ); document.write( "Let the shorter leg be \"x\".
\n" ); document.write( "Longer leg = \"x+1\"
\n" ); document.write( "Hypotenuse = \"2x-1\"
\n" ); document.write( "-----
\n" ); document.write( "Equation:
\n" ); document.write( "(2x-1)^2 = (x+1)^2 + x^2
\n" ); document.write( "4x^2 - 4x + 1 = x^2 + 2x + 1 + x^2
\n" ); document.write( "-------
\n" ); document.write( "4x^2 -4x + 1 = 2x^2 + 2x + 1
\n" ); document.write( "2x^2 -6x = 0
\n" ); document.write( "2x(x-3) = 0
\n" ); document.write( "----
\n" ); document.write( "Positive solution:
\n" ); document.write( "x = 3 (shorter leg)
\n" ); document.write( "x+1 = 4 (longer leg)
\n" ); document.write( "2x-1 = 5 (hypotenuse)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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